Teamteach1 • 1 min read

Sequential Code

def sequential_square(numbers):
    result = []
    for num in numbers:
        result.append(num**2)
    return result

if __name__ == "__main__":
    numbers_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
    sequential_result = sequential_square(numbers_list)
    
    print(f"Sequential Result: {sequential_result}")

Parallel Code

import concurrent.futures

def parallel_square(num):
    return num**2

if __name__ == "__main__":
    numbers_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

    with concurrent.futures.ThreadPoolExecutor() as executor:
        # Using ThreadPoolExecutor to parallelize the task
        parallel_result = list(executor.map(parallel_square, numbers_list))

    print(f"Parallel Result: {parallel_result}")

It will take less time to execute the Parallel Code.